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What Is The Radius Of A Circle Whose Equation Is X2 + Y2 + 8x – 6y + 21 = 0? Units

. The equation can be written. The distance from the center to the circumference is called the radius of the circle.

What is the radius of a circle whose equation is x2 + y2 + 8x 6y + 21
What is the radius of a circle whose equation is x2 + y2 + 8x 6y + 21 from brainly.com

X² + y² + 8x − 6y + 21 = 0. The equation can be written. Add 24 24 to both sides of the equation.

Hence For The Given Circle, The.


X² + y² + 8x − 6y + 21 = 0. If the center of the circle were moved from. The standard form of the equation of the circle is.

Add 24 24 To Both Sides Of The Equation.


Video answer:in the given question. Where (h, k) is the coordinates of the center of the circle and a is the radius. In this problem we have.

And This Question, What We Need To Do Is.


Video answer:we are going to do problem number 57. The equation of the circle is given as. The distance from the center to the circumference is called the radius of the circle.

The Following Equation Is Given To Us And We Are Told.


(x −h)2 +(y−k)2 = r2 ( x − h) 2 + ( y − k) 2 = r 2. R is the radius of the circle. Here we can see that the radius of the circle is 2 units.

The Given Equation Can Be Rewritten In The Standard Form As Follows:


(h, k) is the center of the circle. The equation can be written. In the diagram, a circle centered at the origin, a right triangle, and the pythagorean theorem are used to derive the equation of a circle, x2 + y2 = r2.

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